Raj360

Android app version:- https://drive.google.com/open?id=0BwyIMs3NcEzYbWNManhuLXBOR1U

write a knowledge base add.pl with the following rules: // for two variables  sum(X,Y):-     S is X+Y,    write('sum of '),write(X),write('and '),write(Y),write('is ='),write(S). add:-     write_ln('Enter the first number:-'),     read(First),     write_ln('Enter second number:-'),     read(Second),     S is First+Second,      write('sum of '),write(First),write('and '),write(Second),write('is ='),write(S). now we can close this windows and in the main WINDOW either type  ['add.pl']. or consult the add.pl file. now you can call this funcation via two ways :- ?- sum(5,44). it will give output as  sum of 5 and 44 is 49 or you can call via  add. Enter the first number . :| 45. Enter the second Number . :| 45. sum of 45 and 45 is equal to 90. note i have used sum:- instead of add:- so i have to call it via sum.

well you can either use any way to get simple arithmatics in prolog. For example typing X is 3+2. gives X=5. in prolog . Similarly you can write R is 5*2. it will give R= 10. so doing simple arithmatics is very simple. please note that X or R is capital it can not be a lowercase character otherwise prolog will give output as true. or use this knowledge base .!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!copy from below!!!!!!!!!!!!!!!!!!!!!!!!!!!! sum:-     write_ln('Enter the first number:-'),     read(First),     write_ln('Enter second number:-'),     read(Second),     S is First+Second,      write('sum of '),write(First),write('and '),write(Second),write('is ='),write(S). sub:-     write_ln('Enter the first number:-'),     read(First),     write_ln('Enter second number:-'),     read(Second),     S is First-Second,      write(' difference  of '),write(Firs

So to Write A prolog programming . First Fire up your SWI -PROLOG software. then you will see something like this . Welcome to SWI-Prolog (threaded, 64 bits, version 7.4.2) SWI-Prolog comes with ABSOLUTELY NO WARRANTY. This is free software. Please run ?- license. for legal details. For online help and background, visit http://www.swi-prolog.org For built-in help, use ?- help(Topic). or ?- apropos(Word). ?- _ 1. So now go to File>NEW.... and give any name to knowledge base file. I Give it factorial .pl 2.  now write the follwing fact and rules . fact(0,1) . fact(N,R):-  N>0, N1 is N-1, fact(N1,R1), R is N*R1. now press ctrl +s to save  . 3. now close this windows . 4. now in the main window goto file > Consult..... and select your factorial.pl 5. now you can type query like fact(5,X). it will return X=120. done..... here are some screen shot :

This program takes an input string From user and tell if the given string is present in the String or not Example: This is always true pattern-> is  output -> pattern found  and if pattern input -> zxc output -> No match found  NOTE: CODE:: BLOCKS IS USED in editing and compiling the source code .... +++++++++++++++++++++++++++++C Source Code ++++++++++++++++++++++++++++++ #include <stdio.h> #include <conio.h> void main () { char str[999],pattern[999]; int flag=0,i,j=0,loc; printf("Enter the string \n"); gets(str); printf("Enter the string to find pattern\n"); gets(pattern); for(i=0;str[i]!='\0';i++) { /// main for loop     if(flag==1) break;     if(str[i]==pattern[0])     {/// a match is found         i++;         flag=1; loc=i;         for( j=1;pattern[j]!='\0';j++)         {             if(str[i]!=pattern[j])             {             flag=0

NOTE : YOU CAN DOWNLOAD EXE FILE HERE: SIEVE.EXE SORUCE CODE (RTF): source.cpp click here   1  #include <iostream>  2  #include <conio.h>  3  using namespace std ;  4  int main ()  5   6  {  7   8  int number , n = 2 ;  9  cout << "Program to find out Prime number by sieve method\n\n\a" ; 10  11  cout << "Enter upto which number you want to find out the prime number\n" ; 12  cin >> number ; 13  int arr [ number ]; 14  for ( int i = 0 ; i < number ; i ++) 15  arr [ i ]= i + 1 ; 16  cout << "  Original number:\n" ; 17  18  for ( int i = 0 ; i < number ; i ++) 19  { 20  21  22      cout << arr [ i ]<< "\t\a" ; 23  24  } 25  while (( n * n )< number )  // while n 2  is less than original  number 26  27  { 28  29  for ( int i = n ; i < number ; i ++) 30  { 31  if ( arr [ i ]% n == 0 ) 32  { 33  arr [ i ]=- 1 ; 34

Q: Write A C++ program to find out the largest as well as the second largest element in an array(user input the elements first)? note that every number is treated as a unique so largest or second largest can not be the same. FOr EXAMPLE : 45 45 32 78 9 12 in this answer should come as largest =45 and second largest=32 EXAMPLE 2 :  12 10 11 4 10 12 23 in this answer should be like largest=233 and second largest =12  code here source : click here Executables: LARGEST AND SECOND LARGEST.EXE (click here)

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